0=0.0002*x^2+2*x+0.0002

Solution for 0=0.0002*x^2+2*x+0.0002 equation:

0=0.0002x^2+2x+0.0002

We move all terms to the left:

0-(0.0002x^2+2x+0.0002)=0

We add all the numbers together, and all the variables

-(0.0002x^2+2x+0.0002)=0

We get rid of parentheses

-0.0002x^2-2x-0.0002=0

a = -0.0002; b = -2; c = -0.0002;
Δ = b2-4ac
Δ = -22-4·(-0.0002)·(-0.0002)
Δ = 3.99999984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{3.99999984}}{2*-0.0002}=\frac{2-\sqrt{3.99999984}}{-0.0004}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{3.99999984}}{2*-0.0002}=\frac{2+\sqrt{3.99999984}}{-0.0004}
$